Abox contains 15 resistors. twelve of them are labelled 50ω and the other three are labeled 100ω. what is the probability that the second resistor is 100ω, given that the first resistor is 50ω?

Answer : P(second resistor is 100ω , given that the first resistor is 50ω) is given by

Explanation :

Since we have given that

Total number of resistors =15

Number of resistors labelled with 50ω = 12

Number of resistors labelled with 100ω =3

Let A: Event getting resistor with 50ω

B: Event getting resistor with 100ω

Since A and B are independent events .

So,

Now, According to question , we can get that

So,

So, by using the conditional probability , which state that

So, P(second resistor is 100ω , given that the first resistor is 50ω) is given by

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

correct

step-by-step explanation: