Find the equation perpendicular to the line y=−3x+5 that passes through point (2, 6).

Given equation of line y=−3x+5.

On comparing with slope-intercept form y=mx+b, we can see that m=-3.

So the slope of the given line is -3.

We are given that lines are perpendicular.

Slopes of perpendicular line are reciprocal and opposite in sign.

We got slope of given line -3. The reciprocal of -3 is -1/3 and opposite sign of -1/3 would be 1/3.

So, the slope of the required equation of line would be 1/3.

We are given a point (2, 6).

We got a point and slope. So we can apply point-slope form directly.

y-y1 = m(x-x1)

y-6 = 1/3 (x-2).

Distributing 1/3 on right side.

y-6 = 1/3 x - 3/2

Adding 6 on both sides, we get

y-6+6 = 1/3 x - 3/2 +6

Simplifying fractions -3/2+6 by taking common denominator, we get

-3/2+6/1 = -3/2 + 12/2 = (-3+12)/2 = 9/2

Therefore, the required equation will be

y = 1/3 x +9/2

the answer is d. 75%

a

step-by-step explanation:

when a number is between two straight lines it means the absolute value.

to find absolute value you need to know how many numbers is that number away from 0.

when finding absolute value the number will always come out positive

so absolute value of -3 is 3

absolute value of 3/2 is 3/2

absolute value of -2 is 2

absolute value of 3.5 is 3.5

absolute value of -1 is 1

now put these numbers in order:

a)   |-1|, |3/2|, |-2|, |-3|, |3.5|