Given f(x) = 1/2x - 5, find f^-1(x) a. f^-1 (x) = -2x+10 b. f^-1(x) = 2x+5 c. f^-1(x) = 2x-10 d. f^-1(x) = 2x+10

f^-1(x) = 2x + 10 → d

let y = x - 5

rearrange making x the subject

x - 5 = y

add 5 to both sides

x = y + 5

multiply both sides by 2

x = 2y + 10 ⇒ f^-1(x) = 2x + 10

s

3.how is solving radical equations different than solving linear equations?

step-by-step explanation:

the correct answers i think are b. and d.

give me brainliest if it is correct!