Aprobability experiment consists of rolling a fair 6 -sided die. find the probability of the event below. rolling a number greater than 4

A six sided die has a 1 in 6 probability of rolling any number.
Out of the numbers 1, 2, 3, 4, 5, and 6, two numbers , 5 and 6, are greater than four.
This mean that out of six possibilities, two will be greater than four, so there is a 2 in 6 probability of rolling a number higher than 4. This can be simplified to 1 in 3.

The probability of rolling a number greater than four on a six sided die is 1 in 3, or 1/3

Set square i think so

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for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

1 the 1st term, 3 the 2nd term, 6 the 3rd term,etc.

note the following:

from the 1st term (1) to the 2nd term (3), we go up by 2,from the 2nd term (3) to the 3rd term (6), we go up by 3from the 3rd term (6) to the 4th term (10), we go up by 4, andfrom the 4th term (10) to the 5th term (15), we go up by 5.

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for