If ron has 30 acres of grazing land for his cattle and each cow requires 3/4 of an acre, how many cattle can his land support? a.30 b.40 c.60 d.120

Ron has 40 cattle.

B is correct.

Step-by-step explanation:

Ron has 30 acres of grazing land for his cattle.

Each cattle requires of an acre.

Let us consider n number of cattle.

Total land graze by cattle =

This should be less than equal to 30

We get an equation

Solve for n

Hence, Ron has 40 cattle.

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation:

x² + 11x + 18 < 0  

[-11 ± sqrt(121 - 72)]/2 = (-11 ± 7)/2  

solution: (-9, -2)

step-by-step explanation: