How do you find a vector of length 10 in the direction of v equals=left angle 3 comma negative 2 right angle 3,−2?

Your vector will be 10 times the unit vector in that direction. The unit vector is found by dividing the given vector by its length.

|| <3, -2> || = √(3² +(-2)²) = √13

Your vector of length 10 is then

... V = (10/√13)<3, -2> = <(30/13)√13, (-20/13)√13> ≈ <8.32, -5.55>

x = 25

step-by-step explanation:

a^2+b^2=c^2

7^2+24^2=c^2

49+576=625

sqrt625=25

x=25

i dont know sorry

step-by-step explanation: