Mathematics, 09.07.2019 22:30 nana54muller
In segment addition how do i find x when de = x - 2, ef = x + 5, and df = 9
Answers: 1
![\bf D\underset{\leftarrow DF=9\to \qquad }{\stackrel{x-2}{\rule[0.35em]{10em}{0.25pt}}E\stackrel{x+5}{\rule[0.35em]{15em}{0.25pt}}}F \\\\\\ DF=DE+EF\implies \stackrel{DF}{9}=\stackrel{DE}{(x-2)}+\stackrel{EF}{(x+5)}\implies 9=2x+3 \\\\\\ 6=2x\implies \cfrac{6}{2}=x\implies 3=x](/tpl/images/0071/0226/6b76c.png)
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In segment addition how do i find x when de = x - 2, ef = x + 5, and df = 9...
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