A) 22-2•6=? b) 6-1/4•16+21 divided by 3=? c ) ( 8-5) ( 5-3) to the second power=?

The question has been solved based on the assumption that • represents multiplication operation

We will follow the rule of BODMAS to solve the questions. BODMAS means we solve the expression within the bracket first, then conduct division operation, followed by multiplication, addition and subtraction.

Part A

22-2•6

Let 22-2•6 be X

⇒ X = 22 - 12 (Conducting multiplication  operation first)

⇒ X = 10 (Conducting subtraction next)

Part B

6-1/4•16+21 divided by 3 indicates that the first part of the expression ( 6-1/4•16+21) needs to be divided by 3.

Let 6-1/4•16+21 divided by 3 be Y

⇒ Y = (6-1/4•16+21) ÷ 3

⇒ Y = (6-0.25•16+21) ÷ 3 (Solving the bracket first and starting with the division operation)

⇒ Y = (6-4+21) ÷ 3 (Conducting the multiplication operation next)

⇒ Y = (6-17) ÷ 3 (Conducting the addition operation next)

⇒ Y = (11) ÷ 3 (Conducting the subtraction operation next)

⇒ Y = 3.333... (Moving out of the bracket and conducting the remaining operation)

Hence, Y = 3.333...

Part C

(8-5) (5-3) to the second power indicates that the brackets need to be solved first. Also, power operation is conducted before division or multiplication.

Let (8-5) (5-3) to the second power be Z

⇒ Z =  (3) (2) to the second power (Solving the brackets first)

⇒ Z =  (3) (2²) (Conducting the power operation next)

⇒ Z =  (3) (4)

⇒ Z =  12 (Conducting the multiplication operation next)

Hence, Z = 12.

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i