The ages of three brothers are consecutive integers with a sum of 96. how old are the brothers?

consecutive integers have a difference of 1 between them

let the brothers have ages n , n + 1 and n + 2 thus

n + n + 1 + n + 2 = 96

3n + 3 = 96

subtract 3 from both sides of the equation

3n = 96 - 3 = 93

divide both sides by 3

n = = 31

The ages are 31 , 32 and 33

45

step-by-step explanation:

since we know that the two functions are equal, f (x) = g

(x), therefore when we equate the two equations the result should be similar to

3x = x – 4:

a. f(x) = 3x, g(x) = x – 4

equating the two functions:

3x = x – 4             (correct)

so we now got our answer (a)