Find an equation for the line that passes through the given point and satisfies the given conditions. 11) 11) p = ( 9 , 2 ); perpendicular to v = 4 i + 4 j

You can use the direction vector as the coefficients of x and y for a line through (0, 0) perpendicular to that direction: x + y = 0. (A common factor of 4 can be removed from the coefficients.)

Translating the line up 2 and right 9, so it goes through the given point, we get ...

... (x -9) +(y -2) = 0

or

... x + y = 11

i hope this is what you were looking for.

see attached graph