What is the height of an isosceles trapezoid, if the lengths of its bases are 5m and 11m, and the length of a leg 4m. show your work. you!

An isosceles trapezoid has 2 parallel sides and equal non-parallel legs. The height of the isosceles trapezoid is 2.65 m

Because the trapezoid is isosceles, the 2 legs of the trapezoid will be equal.

I have added an attachment that represents the given trapezoid.

From the attachment, we have:

--- length of the leg

---- base of the triangle formed by the leg of the trapezoid

The height (h) is calculated using the Pythagoras theorem as follows:

So, we have:

Collect like terms

Take square roots of both sides

Hence, the height of the trapezoid is 2.65 m

Read more about isosceles trapezoid at:

link

Let EB and CF be two heights. Then quadrilateral EBCF is rectangle, so BC=EF=5 m. It is given that bases are BC=5 m and AD=11 m. Triangles ABE and DCF are congruent, thus,

Consider right triangle ABE, by the Pythagorean theorem

8

step-by-step explanation:

this is a subtraction problem.

10 - 2 = 8

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.