Find four consecutive integers such that twice the first sub trcted form the sim

Integers=x,x+1,x+2,x+3

(x+1+x+2+x+3)-2x=16

3x+6-2x=16

x=16-6

x=10 answer for the first integer.

10,11,12,13 are all the integers.

proof:

11+12+13-2*10=16

36-20=16

16=16

so, converting firstly the mixed fractions to improper fractions and then "adding".

answer:   b

step-by-step explanation:

x2 = 16

x can not be a negative number because 16 is positive

the only answer would be positive 8