The sum of two numbers is 11. the larger number is 1 less than twice the smaller number. what are the two numbers? which equations can be used to express the problem as a system of two linear equations in slope-intercept form? select all that apply. y = 2x –1 y = x –11 y = x + 11 y = 11 – x

y = 2x - 1 and y = 11 - x

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15