The perimeter of a rectangle 310m the lenght is 25m greater than the width what are the length and width of a rectangle

Let x be the width.

length is 25m greater than the width, hence, x+25 will represent the length.

perimeter is 310m

W=x

L= x+25

Solution:

P=2(L+w)

310m=2[(x+25m)+x)]

combine like terms

310m=2(2x+25m)

310m=4x+50m

transpose

310m-50m=4x

260m=4x

divide both sides by 4

65 = x

now that we have the measurement of the width. get the measurement of the length

Length= x+25m

L=65m+25m

L=90m

10 * 563.67 = 5636.7

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2