An empty 6-gal water jug weighs 0.5 lb. with 3 c of water inside, the jug weighs 2 lb. which equation models the jug’s weight y when it contains x cups of water? a) y= 0.5x-0.5 b) y= 0.5x+0.5 c) y= -0.5x-0.5 d) y= -0.5x+0.5

J = jug

J = 0.5x + 0.5

the slope would be 2/3 because that would leave pounds when multiplied by cups.

add 0.5 for the weight of the water jug

y = (2/3)x + 0.5

                        hope it helps

3, nah jk it's 2

step-by-step explanation:

it is 3 cause i'm sanic

i think 1: 2

step-by-step explanation: