Atree of height y meters has, on average, upper b branches, where upper b equals y minus 3. each branch has, on average, n leaves where n equals 2 upper b superscript 2 baseline minus upper b. find the average number of leaves on a tree as a function of height.

we are given

number of branches is

number of leaves on each branch

the average number of leaves = (number of branches)*(number of leaves on each branch)

so, we can plug values

we get

now, we can plug values

now, we can simplify it

............Answer

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3