Darren wins a coupon for 4$ off the lunch special for each of 5 days. he pays $75 for his 5 lunch specials. write and solve an equation to find the original price p for one lunch special

Value of each coupon = $4.

Total number of lunches taken = 5.

Let us assume original price for one lunch special = p.

Total amount paid in all 5 lunches taken = $75.

We can setup an equation now,

Number of lunches( cost of each lunch - discount value of each coupon) = $75

Plugging values,

5 ( p - 4) = 75.

This is the required equation to find the original price p for one lunch special.

Distributing 5 over (p -4), we get 5*p +5*-4 =  5p -20.

5p -20 =75.

Adding 20 on both sides.

5p -20+20 =75+20

5p = 95.

Dividing both sides by 5, we get

5p/5 = 95/5

p = 19.

Therefore, the original price is $19 for one lunch special.

option 1

data plot with   3 dots over 33, 1 dot over 34, 2 dots over 35, no dot over 36, 1 dot over 37, 2 dots over 38, 4 dots over 39, and 2 dot over 40.

answer:

payment just for service  

→

$

87.12

payment for service including tax

→

$

94.09

explanation:

service only with 20% tip  

→

$

72.6

(

1

+

20

100

)

=

$

87.12

in the opening of the question the word 'service' is associated only with the pretax value.

the closing part of the question asks: how much did she pay for the  

service

−−−−−−  

so technically the answer is  

→

$

72.6

(

1

+

20

100

)

=

$

87.12

however, the intention of the question provider may have been that your answer is to be  

$

87.12

(

1

+

8

100

)

=

$

94.09

to 2 decimal places.

'

payment just for service  

→

$

87.12

payment for service including tax

→

$

94.09

tony b

mar 21, 2017

answer:

trying to explain it another way

explanation:

service charge  

.

→

$

72.60

20% tip  

20

100

×

$

72.60

=

$

14.52

−−−−−−  

←

add

$

87.12

tax  

8

100

×

$

87.12

=

$

6.97

−−−−−  

←

add

$

94.09

related questions