The coordinates of the vertices of △jkl are j(3,4) k(3,1) l(1,1). coordinates of the vertices of △j’k’l’ are j’(-3,-5) k’(-3,-2) l’(-1,-2). drag and drop the answers into the boxes to correctly complete dragon drop answers into the boxes to correctly complete the statement. a sequence of transformations that maps △jkl to j’k’l’ is a (fill blank) followed by a (fill blank). answer choices are : rotation of 90 degrees counterclockwise about the origin. rotation of 180 degrees about the origin. translation 1 unit down. translation 1 unit left.

We are given coordinates of triangle △JKL are J(3,4) K(3,1) L(1,1) and

△J’K’L’ are J’(-3,-5) K’(-3,-2) L’(-1,-2).

We know, rotate a figure about 180° about the origin, (x,y) would result (-x,-y).

So, we can  "Rotate 180° about the origin." first.

After rotating 180° about the origin, J(3,4) K(3,1) L(1,1) points would transform to new coordinates J(-3,-4) K(-3,-1) L(-1,-1).

If we move 1 unit down. So the new coordinate of (-x,-y) would become (-x, -y-1).

J(-3,-4) K(-3,-1) L(-1,-1) coordinates would transform to J(-3,-4-1) K(-3,-1-1) L(-1,-1-1).

And those are coordinates exactly J’(-3,-5) K’(-3,-2) L’(-1,-2).

Those are the given coordinates of transformed triangle △J’K’L’.

So, the steps of transformations can be summarize

First step : Rotation of 180 degrees about the origin.

Second step:  Translation 1 unit down.

dilation scale factor 2: starting with δabc, draw the dilation image of the triangle with a center at the origin and a scale factor of two. notice that every coordinate of the original triangle has been multiplied by the scale factor (x2). dilation with scale factor 2, multiply by 2.