The coordinates of the vertices of △jkl are j(3,4) k(3,1) l(1,1). coordinates of the vertices of △j’k’l’ are j’(-3,-5) k’(-3,-2) l’(-1,-2). dragon drop the answers into the boxes to correctly complete dragon drop answers into the boxes to correctly complete the statement. a sequence of transformations that maps △jkl to j’k’l’ is a (fill blank) follwed by a (fill blank). answer choices are : rotation of 90 degrees counterclockwise about the origin. rotation of 180 degrees about the origin. translation 1 unit down. translation 1 unit left.

Given coordinates of △JKL are J(3,4) K(3,1) L(1,1) and

△J’K’L’ are J’(-3,-5) K’(-3,-2) L’(-1,-2).

We know, when we rotate a figure about 180 degrees about the origin, the coordinates (x,y) would result (-x,-y).

So, first step should be "Rotation of 180 degrees about the origin."

After rotating 180 degrees about the origin, J(3,4) K(3,1) L(1,1) points would transform to  J(-3,-4) K(-3,-1) L(-1,-1).

Now, we will move 1 unit down. So the new coordinate of (-x,-y) would become (-x, -y-1) and J(-3,-4) K(-3,-1) L(-1,-1) coordinates would transform to exactly J(-3,-4-1) K(-3,-1-1) L(-1,-1-1)  => J’(-3,-5) K’(-3,-2) L’(-1,-2).

And those are the coordinates of transformed triangle △J’K’L’.

So, the steps of transformations are as following:

Setp 1) Rotation of 180 degrees about the origin.

Setup 2) Translation 1 unit down.

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."

central angle of a triangle has the same measure as its intercepted arc.

step-by-step explanation: