Rob had twice as much money as sam. then sam gave rob 1 quarter, 2 nickels, and 3 pennies. rob then gave sam 8 dimes. if they now have the same amount of money, how much money did rob originally have? (steps ! )

Let the initial amount that Sam had be x.

Then, since Rob had twice as much as Sam, Rob's money would be 2x.

Now, Sam gave 1 quarter, 2 nickels and 3 pennies to Rob.

Let's convert all of them into pennies.

1 quarter + 2 nickels + 3 pennies = 25 + (2 x 5) + 3

                                                      = 38 pennies

So, Sam's amount is x - 38 and Rob's amount is 2x + 38.

Now, Rob gives 8 dimes to Sam.

8 dimes = 80 pennies.

So, Sam's amount now is x - 38 + 80 = x + 42 and

Rob's amount is 2x + 38 - 80 = 2x - 42

Its given that these two amounts are same.

So,  2x - 42 = x + 42

2x - x = 42 + 42

x = 84

Rob's original amount = 2x = 2(84) = 168 pennies.

                                                         = $1 + 6 dimes + 1 nickel + 3 pennies

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

answer: 100

step-by-step explanation: