In a list of 30 integers, 18 of the integers are multiples of 5. if 10 of the multiples of 5 are odd integers, what is the maximum number of even integers in the list?

Without knowing anything about the other 12 integers, you could assume that they are all even, just not divisible by 5.  

In additon 18 - 10 = 8 integers that are divisible by 5 all end in zero which is even.

So you have 8 + 12 which is 20 integers that could be even. Answer

24

step-by-step explanation:

if it takes 8 pounds to make 12 divide 12 by 8 and you get 1.5, 1.5 x 16 = 24