Suppose that three fair coins are flipped independently. what is the probability that exactly two of them come up heads?

The probability of the first 2 being heads and the next one being a  tail

= (1/2)^3  = 1/8

2 heads and 1 tail can happen in  3 different ways:-

HHT HTH THH

So probability of 2 H and 1 T  = 3 * 1/8 = 3/8 Answer

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.