For football tryouts at a local school, 12 coaches and 42 players will split into groups. each group will have the same numbers of coaches and playerswhat is the greatest number of groups that can be formed ? how many choaches and players will be in each of these groups?

Find the Largest common factor of 12 and 42:

Factors of 12:  1, 2, 3, 4, 6, 12

Factors of 42: 1, 2, 3, 6, 7, 14, 21, 42

The largest common factor is 6, so they will be split into 6 groups.

12/6 = 2

42 / 6 = 7

Each group will have 2 coaches and 7 players.

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)