Find the equation of the line described. perpendicular to y = 6x + 5; passing through the point (3, 2).

Hello!

To find the line perpendicular to y = 6x + 5, you need to find -1/m. -1/m will give you the slope of the perpendicular line. After finding the slope, you need to substitute (3, 2) into the perpendicular without the y-intercept and solve for the y-intercept then.

In the given line, the slope is 6, or m = 6.

-1/m = -1/6

y = -1/6x + b

Now, we need to find the y-intercept.

2 = -1/6(3) + b

2 = -3/6 + b

2 = -1/2 + b (add -1/2 to both sides)

b = 5/2

Therefore, the equation of the line perpendicular to y = 6x + 5 is y = -1/6x + 5/2.

the slope of the line is 60

one point on the line is (40,10)

step-by-step explanation:

in the equation outside the parenthesis the equation always tells you the slope. in this case it is 60.

in the parenthesis is also says 40 which is x because it is near the x and 10 is y because it is near y.

5 pm

step-by-step explanation: