He service elevator in a high-rise building travels between the lowest underground parking level and the seventeenth story of the building. the lowest parking level is 15 meters below street level, and the seventeenth story is 51 meters above street level. if the elevator rises at a rate of 2 meters per second, how long, in seconds, could a person ride the elevator when starting from the lowest level? assume the elevator makes no extra stop. a.

First of all, we need to figure the TOTAL distance the elevator will travel from below street level to above street level. We know it's 15 meters below street level and 51 meters above street level, so let's add those two numbers.

51 + 15 = 66.

Now, we know the total distance the elevator will travel. We need to divide the distance that will be traveled by the rate of 2 meters per second.

66 / 2 = 33

There's your answer. The elevator will take 33 seconds to travel from the lowest story below street level to the highest story above street level.

A person could ride the elevator for a total of 33 seconds.

Hope this answer helped. :)

d

step-by-step explanation:

by observation, we can see that the the graph is simply the graph of y = |x| that has been shifted 4 units downwards and 3 units to the left.

we can recognize in choice d :

y = | x + 3 |   - 4 (rewriting in general form)

y = | x - (- 3) |   - 4

the "-4 " term means   that the graph has been shifted by 4 units in the negative y direction

the "-3 " term means   that the graph has been shifted by 3 units in the negative x direction

this matches our observation of the graph described above.

the amount you'd have after the work is $1.55

step-by-step explanation:

you subtract 95% from $31.