If f(x)=2-x^(1/2) and g(x)=x^2-9 what is the domain of g(x)-f(x)

g(x) - f(x) = x^2 - 9 - (2 - x^1/2)

= x^2 + x^1/2 - 11

negative x gives no real value for this function because x^1/2 is not defined for negative x

the domain is  x >= 0   or in interval notation [0, ∞)  

the 3rd option is right

step-by-step explanation:

answer: i think one of the answer is $150 and $300?

step-by-step explanation: