Find all sets of two consecutive positive odd integers with a sum that is at least 8 and less than 24. right an inequality for this problem and graph your solution

An odd integer is denoted by 2n+1 where n is an integer.

First odd integer = 2n+1

Next odd integer = 2n+3

8 ≦ (2n+1)+(2n+3) < 24

8 ≦ 2n+1+2n+3 < 24

8 ≦ 4n+4 < 24

Divide through by 4

2 ≦ n+1 < 6

Subtract 1 for all three sides:

1 ≦ n < 5

n ∈ {1,2,3,4}  

 {2n+1, 2n+3}  {1,3}, {3,5}, {5,7}, {7,9}, (9,11}

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.

answer: both chords and diameters have two endpoints on a circle. diameters must intersect the center of a circle.