Write the standard form of the line that passes through the given points. include your work in your final answer. type your answer in the box provided or use the upload option to submit your solution. (3,1) and (-2,3).

The equation would be 2x + 5y = 11.

To find this, we first have to find the slope of the line. The slope formula is below.

m (slope) = (y2 - y1)/(x2 - x1)

In which (x1, y1) is the first point and (x2, y2) is the second. So we plug in to solve.

m = (3 - 1)/(-2 -3)

m = 2/-5

Now that we have the slope, we can use it along with a point to get the slope intercept form.

y = mx + b

3 = -2/5(-2) + b

3 = 4/5 + b

11/5 = b

Now that we have the equation of y = -2/5x + 11/5 we can manipulate it into standard form.

y = -2/5x + 11/5 > add 2/5x to both sides

2/5x + y = 11/5 > multiply both sides by 5

2x + 5y = 11

the slope of the line is 60

one point on the line is (40,10)

step-by-step explanation:

in the equation outside the parenthesis the equation always tells you the slope. in this case it is 60.

in the parenthesis is also says 40 which is x because it is near the x and 10 is y because it is near y.

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.