Will give brainliest answer! calculate the percent error.

From the given tabular data,

Volume of water (V) = 50.0 ml

Mass of water (m) = 49.7 g

So, the density of water (ρ) = Mass / Volume

or,                                          = 49.7 g /50.0 ml = 0.994 g / ml

Actual value of the density of water (ρ') = 0.998 g /ml

So, the percentage error in the density of water

        = [( actual value - observed value) / actual value ] ×100

or,    = [ (0.998 g /ml - 0.994 g / ml ) / 0.998 g /ml ] ×100

or,    = 0.4 %

Hence, the required % error in the density of water will 0.4 %.

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