Find the 92nd term of the arithmetic sequence -29,-22,-15

The value of the 92nd term is 608.

In order to find this, you have to first find the equation of the sequence. In order to find that equation, first make two ordered pairs using x as what number it is in the sequence and y as the value. Therefore you have the following ordered pairs: (1, -29) and (2, -22). Given that, we can find the slope by using the slope formula below.

m (slope) = (y2 - y1)/(x2 - x1)

m = (-22 - -29)/(2 - 1)

m = 7/1

m = 7

Now that we have a slope of 7, we can find the intercept using slope intercept form and a point. We'll use (1, -29) as the point.

y = mx + b

-29 = 1(7) + b

-29 = 7 + b

-36 = b

Now that we have the slope and intercept, we can write the equation.

f(x) = 7x - 36

Now we can plug 92 in for x to find the answer.

f(92) = 7(92) - 36

f(92) = 644 - 36

f(92) = 608

b) k’(6, 4); l’(3, 3)

step-by-step explanation:

a 270° clockwise rotation maps every point (x, y) to (y, -x). (it negates the x-coordinate and then switches it and the y-coordinate.)

this means the endpoints of the side congruent to kl, k' and l', would be mapped as:

k'(-4, 6)→(6, 4)

l'(-3, 3)→(3, 3)

i don't know, but that looks pretty bad. my school passed us unless we failed in all the subjects, but idk abt ur school's rules.

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