To two decimal places, find the value of k that will make the function f(x) continuous everywhere. 3x+k

solution:

we are consider the following function,

f(x)=3x+k,x\leq 3

=kx^{2}-6,x>3

\lim_{x\rightarrow 3^-}(3x+k)=9+k

\lim_{x\rightarrow3^+}

(kx^{2}-6)=9k-6

so the left and right limits are equal.

therefore, the function is continuous at x=3

so,the therom of the function is continous at x=3

9k-6=9+k

8k=15

k=15/8

=1.875

therefore,the value of k=1.875

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)

answer: i could not see part the question so ill explain how to get the answer

step-by-step explanation: for instance the distance she travele d is 10 and she traveled the same amout each mile so do 10 divided by how many miles she drove each time and you ge your answer.