Acar leaves a town at 110 kilometers per hour. how long will it take a second car, travelling at 135 kilometers per hour, to catch the first car if it leaves 1 hour later?

Let t = travel time of the second car

then, (t+1) = travel time of the first car (since the first car starts start 1 hr before the second car)

When the second car catches the first car, they will have traveled the same distance

Write a distance equation: dist = speed * time

135*t = 110*(t+1)

135t = 110t + 110

25t = 110

t =110/25

t = 22/5 hours or 4.4 hours

Since 0.4 hours corresponds to 0.4*60 = 24 minutes, the total time is 4 hours and 24 minutes

So, the second car will catch the first car in 4 hours and 24 minutes

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

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