Ahorse race has 13 entries and one person owns 5 of those horses. assuming that there are no ties, what is the probability that those five horses finish first, second, third, fourth, and fifth (regardless of order)? the probability first, second, third, fourth, and fifth is nothing.

There are 13 entries in total  

The owner has 5 horses.

If each horses has  the same  probability of winning, then the probability that the owners

Horses will come in first, second, third, and fourth will be as follows:

It was only specified that one of these horses needed to be in each position  

This makes it is a combination type problem because order does not matter  

We 5 horses

The probability that one of those 5 horses will be first is 5/13

The probability that one of those remaining  4 horses will be second is 4/12

The probability that one of those remaining  3 horses will be third is 3/11

The probability that one of those remaining 2 horses will be fourth is 2/10

The probability that one of those remaining 1 horses will be fifth is 5/9    

The total probability is that 0.00389

hi!

i believe that john has 55 pieces of candy left.

!

answer: a) (0,0), (1,1), (2,8), and (3,27).

step-by-step explanation:

0^3=0

1^3=1

2^3=8

3^3=27

in effect, the exponential equation for this would me y=3^x. each x-coordinate cubed is giving the y coordinate, so a is your answer : )