Aparty rental company has chairs and tables for rent. the total cost to rent 2 chairs and 3 tables is $ 25 . the total cost to rent 6 chairs and 5 tables is $ 49 . what is the cost to rent each chair and each table?

Let c= cost to rent each other

Let t= cost to rent each other

2c+3t=25

6T+5T=49

Multiply the 2nd equation by (-2) and add equation together  

2c+3t=25

-12c-10t= 98

2t=98

T=49

Put this value into the 1st equation solve c

2c+3(49)=49

2c+147=49

2c=98

C=49

Cost to each chair and table are same 49.

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."

a c

step-by-step explanation: