1) if b is between a and c, ab=10 and ac=28, what is the value of bc? 9 18 19 38 2) if b is between a and c, ab=6x, bc=8x and ac=42, what is the value of x? 3 14 18 24 3) if b is between a and c, ab=2x-1, bc=3x+5 and ac=24, what is the value of ab? 4 7 12 17

One

AB + BC = 28

AB = 10

10 + BC = 28

BC = 28 - 10

BC = 18

Two

AB + BC = AC

AB = 6x

BC = 8x

6x + 8x = 42

14x = 42

x = 42/14 = 3

Three

AB = 2x - 1

BC = 3x + 5

AB + BC = 24

2x - 1 + 3x + 5 = 24

5x + 4 = 24

5x = 24 - 4

5x = 20

x = 20/5

x = 4

AB = 2x - 1

AB = 2*4 - 1

AB = 7

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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