One number is 8 times a first number. a third number is 100 more than the first number. if the sum of the three is 690, find the numbers.

Three numbers are n, 8n, and (100+n).

Their total is 690.

the three numbers

n + 8n + (n+100) = 690

10n + 100 = 690 . . . . . . . simplify

10n = 590 . . . . . . . . . . . . subtract 100

n = 59

8n = 472

n +100 = 159

The three numbers are 59, 472, and 159.

the equivalent expression are always the hardest ones but you look at the gcf also

step-by-step explanation:

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.