In 2000, canada produced 3.0 million new motor vehicles. in 2006, it produced 2.5 million. write the linear equation (in slope-intercept form)that models the number of vehicles

a.) -.071 x+9
b.) -.083 x+3
c.) -.074 x+4
d.) -.065 x+0
e.) -.068 x+2
f.) -.058 x+12
g.) -.062 x+10
h.) -.079 x+5

To begin, you are given two point that this function would intercept: (0,3) where the 0 is the original year (2000) and 3 is the amount of million cars sold. The next point would be (6,2.5) Where the 6 is the 6 years later and the 2.5 is the 2.5 million cars sold. Since we have 2 points, we can work out the gradient by finding the rate of change in y and dividing by the rate of change in x:


We then substitute in the points:









Because we started on the y-intercept of (0,3), we already have our intercept value of 3. If we did not start with the y-intercept given, we could substitute in a point to solve for it:

Using point (2.5,6):






Hope this helps :)

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