2e^3x=4e^5x. find x using log. show work

2 = 4

= 2divided both sides by 2

ln ( ) = ln (2 ) applied "ln" to both sides

ln ( ) = ln 2 + ln tex] e^{5x} [/tex] ) applied the log product rule

3x = ln 2 + 5x applied "ln e = 1"

-2x = ln 2 subtracted 5x from both sides

x = divided both sides by "-2"

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )

answer: 3.26019516

step-by-step explanation: