Three consecutive odd integers have a sum of 39. find x, the smallest of the three integers

The three integers are 11, 13, and 15.

Explanation:

We shall consider the integers as x, (x+2), and (x+4). The sum of these is 39, so we can write:

x+(x+2)+(x+4)=39

Open the brackets and simplify.

x+x+2+x+4=39

3x+6=39

Subtract 6 from each side.

3x=33

Divide both sides by 3.

x=11

Therefore: (x+2)=13 and (x+4)=15

hope this helps!

step-by-step explanation:

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its c or d   take a lucky guess my dude