Define a variable write an equation and solve the problem. the width of a rectangle is 3 meters more than one-fourth its length. the perimeter is 10 meters more than twice its length. find the length and width

Let's assume

length of rectangle is L

width of rectangle is W

the width of a rectangle is 3 meters more than one-fourth its length

so,

the perimeter is 10 meters more than twice its length

we know that

perimeter =2(L+W)

so, we get

now, we can simplify it

subtract both sides by 2L

now, we can find L

subtract both sides 3

multiply both sides by 4

so,

length of rectangle is 8 meter

width of rectangle is 5 meter ............Answer

answer: 193

explanation:

200-7 = 193