Correct answers only ! jackie has fewer than 20 h to work on her jewelry. it takes her half an hour to make a necklace and an hour to make a bracelet. she wants to make x necklaces and y bracelets, and she wants at least twice as many bracelets as necklaces. select all inequalities that model this situation.

y = Bracelets

x = Necklaces

Half Hour for the Necklaces; One Hour for the Bracelets; Fewer than Twenty-Hours.

0.5x + y < 20

At Least Twice as many Bracelets, as Necklaces.

y ≥ 2x; x > 0

Answers:

Letter Choices;

(B) 0.5x + y < 20,

(C) y ≥ 2x,

(F) x > 0

Hope that helps : )

choice b is correct

step-by-step explanation:

we have been given the following system of inequalities;

we are required to graph the solution to the system of inequalities. using a graphing tool, the graph of the system is as shown in the attachment. the continuous line represents the graph of while the dotted line represents .

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)