Five less than twice a number is equal to one half the difference of three times the number and 13. find the number.

That number would be -3.

For the purpose of solving this, let that number be x. Now write out the front side of the equation:

2x (twice a number) - 5 (five less than)

2x - 5

Now write out the other side

1/2 (one half of) (3x - 13) (The difference of 3 times the number and 13)

1/2(3x - 13)

Now set the two sides equal to each other and solve

2x - 5 = 1/2(3x - 13) > multiply both sides by 2

4x - 10 = 3x - 13 > subtract 3x from both sides

x - 10 = -13 > add 10 to both sides

x = -3

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

6 on both sides and twelve on the top and the bottom

step-by-step explanation: