What are the x-intercepts of the quadratic function? y = x2 – 3x + 2 a) 2 and 1 b) –2 and 1 c) 2 and –1 d) 1

y = x² - 3x + 2

The x-intercepts can be take by matching the equation to 0, so,

x² - 3x + 2 = 0

Δ = b² - 4.a.c

Δ = -3² - 4 . 1 . 2

Δ = 9 - 4. 1 . 2

Δ = 1

There 2 real roots.

x = (-b +- √Δ)/2a

x' = (--3 + √1)/2.1

x'' = (--3 - √1)/2.1

x' = 4 / 2

x'' = 2 / 2

x' = 2

x'' = 1

Alternative A.

i believe the answer is d.

hope it you! : d

connie < felicia < stew

step-by-step explanation:

stew:

we need to find the slope

m = (y2-y1)/ (x2-x1)

    = (2650-795)/(10-3)

    = 1855/7

265 words per minute

connie:

we need to find the slope

m = (y2-y1)/ (x2-x1)

we have two points (0,0) and (4,800)

m = (800-0)/(4-0)

  m = 800/4

    200 words per minute

felicia:

260 words per minute

200< 260 < 265

connie < felicia < stew