Use the graph to find the bear’s average heart rate when it’s active and when it hibernating

we know that

the rate of a linear equation  is equal to the slope

Step 1

Find the  bear’s average heart rate when it’s active

Let

A(1.5,90)   B ( 2,120)

the slope is equal to

m=(y2-y1)/(x2-x1)

m=(120-90)/(2-1.5)=30/0.5

m=60 heartbeats/min

therefore

the answer part a) is

the bear’s average heart rate when it’s active is 60 heartbeats/min

Step 2

Find the  bear’s average heart rate when it’s hibernating

Let

A(1.5,18)   B ( 2,24)

the slope is equal to

m=(y2-y1)/(x2-x1)

m=(24-18)/(2-1.5)=6/0.5

m=12 heartbeats/min

therefore

the answer part b) is

the bear’s average heart rate when it’s hibernating is 12 heartbeats/min

54 kilometers per hour

step-by-step explanation:

according to rules:

1 km = 1000 meter

which means that 1 meter = 1/1000 km

1 hour = 3600 second [ as 1 hour = 60 min = 60 *60 seconds ]

which means that 1 second = 1/3600 hour

therefore, 1 kilometer/hour =

thus to convert 15 meter per second to kilometer per hour, we multiply 15 to 3.6 kilometer/hour.

15 meter/second=   which is the required answer.