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Mathematics, 13.07.2019 02:30 hrcatena

1. the beginning steps for determining the center and radius of a circle using the completing the square method are shown below: step 1 [original equation]: x2 βˆ’ 6x + y2 βˆ’ 4y = 3 step 2 [group like terms]: (x2 βˆ’ 6x) + (y2 βˆ’ 4y) = 3 step 3 [complete the quadratics]: which of the following is the correct equation for step 3? (x2 βˆ’ 6x + 6) + (y2 βˆ’ 4y + 4) = 4 + (6 + 4) (x2 βˆ’ 6x βˆ’ 3) + (y2 βˆ’ 4y βˆ’ 2) = 4 + (βˆ’3 βˆ’ 2) (x2 βˆ’ 6x + 3) + (y2 βˆ’ 4y + 2) = 4 + (3 + 2) (x2 βˆ’ 6x + 9) + (y2 βˆ’ 4y + 4) = 3 + (9 + 4) 2. using the following equation, find the center and radius of the circle by completing the square. x2 + y2 + 6x βˆ’ 6y + 2 = 0 center: (βˆ’3, 3), r = 4 center: (3, βˆ’3) r = 4 center: (3, βˆ’3), r = 16 center: (βˆ’3, 3), r = 16 3. the beginning steps for determining the center and radius of a circle using the completing the square method are shown below: step 1 [original equation]: x2 + 8x + y2 βˆ’ 6y = 11 step 2 [group like terms]: (x2 + 8x) + (y2 βˆ’ 6y) = 11 step 3 [complete the quadratics]: (x2 + 8x + 16) + (y2 βˆ’ 6y + 9) = 11 + (16 + 9) step 4 [simplify the equation]: (x2 + 8x + 16) + (y2 βˆ’ 6y + 9) = 36 step 5 [factor each quadratic]: which of the following is the correct equation for step 5? (x + 4)2 + (y βˆ’ 3)2 = 62 (x + 8)2 + (y βˆ’ 6)2 = 62 (x βˆ’ 4)2 + (y + 3)2 = 62 (x + 16)2 + (y + 9)2 = 62

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