Suppose a basketball player is an excellent free throw shooter and makes 94% of his free throws (i. e., he has a 94% chance of making a single free throw). assume that free throw shots are independent of one another. suppose this player gets to shoot three free throws. find the probability that he misses all three consecutive free throws. round to the nearest ten-thousandth.

Probability of a failure on 1 throw = 1 - 0.94 = 0.06 or 6%.

Prob (he misses all 3) = 0.06^3 = 0.000216 = 0.0002 to nearest ten thousandth

Prob (he misses all 3) = 0.06^3 = 0.000216 = 0.0002 to nearest ten thousandth

Step-by-step explanation:

hello i am doing good for you that it's summer in your country or state ; )

btw in my country we just have sun and rain as (because i live in the caribbean lol)

also, thx a lot for the points : )