If chuck travels 310 miles and dana travels 295 at the same time, but chuck rate of travel is 3 mph more than dana and they travel the same amount of time, at what speed does doug travel?

Hello!

Let's write this as an equation below.

310/3+d=295/d

As you can see, we can cross-multiply this proportion giving us the equation below.

310d=295(3+d)

310d= 295d+885

Now, we subtract 295d from both sides.

15d=885

Now we divide both sides of the equation by 15.

d=59

Therefore, Dana travels 59 mph.

I hope this helps!

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3