Compare the given dimensions of four triangles. which triangle is possible to construct? side lengths of 5 ft, 12 ft, and 13 ft side lengths of 2 ft, 11 ft, and 15 ft side lengths of 3 ft, 7 ft, and 11 ft side lengths of 4 ft, 8 ft, and 15 ft

The two shorter side lengths of a triangle must add up to be greater than the longest side length of the triangle.

1) side lengths of 5 ft, 12 ft, and 13 ft

5 ft + 12 ft > 13 ft

2) side lengths of 2 ft, 11 ft, and 15 ft

2 ft + 11 ft < 15 ft

3) side lengths of 3 ft, 7 ft, and 11 ft

3 ft + 7 ft < 11 ft

4) side lengths of 4 ft, 8 ft, and 15 ft

4 ft + 8 ft < 15 ft

Based on the four "triangle" dimensions, the only give dimensions that are able to construct a triangle are the first option because the two shorter side lengths (5 ft and 12 ft) are greater than the longest side length (13 ft).

Your answer is 1) side lengths of 5 ft, 12 ft, and 13 ft.

the answer is A side lengths of 5ft, 12ft, and 13ft

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form