Aman has two daughters, one three times as old as the other. the man is five times as old as his older daughter and in 5 years he will be five times as old as the younger. find their present ages.

Let d_one = the oldest daughter

Let d_two = the younger daughter.

Let the father = dad.

d_one= 3*d_two . . . . . . . . . . (1)

dad = 5*d_one . . . . . . . . . . . (2)

dad + 5 = 5*(d_two + 5) . . . .(3)

Now you have to put all this information in a solvable form.

Put (1) into three.

5*d_one + 5 = 5*(d_two + 5) Put (1) into this equation

5*(3*d_two) + 5 = 5*(d_two + 5) Remove both sets of brackets.

15*d_two + 5 = 5*d_two + 25 subtract 5 from both sides.

15*d_two = 5*d_two + 20 Subtract 5*d_two

10*d_two = 20 Divide both sides by 10

d_two = 20/10

d_two = 2

d_one is current 2 *3 = 6

dad is 5*d_one = 5* 6 = 30

Summery

The youngest child is currently 2

the oldest one is currently 2*3 = 6

Dad is currently 30

use an equation of ratios to determine the amount of gas needed to fill the tank.

    0.2             0.8

  =    

288.75             x

                                                              231 gal

so, 0.2x = (0.8)(288.75 gal), and x = = 1155 gal.

                                                                0.2

it would take 1155 gal. to fill the tank.

the cost would be

1155 gal         $3

* = $3465   (answer)

      1           1 gal

hope this you

answer: h

step-by-step explanation: