Answer the whole question and explain! one student ate 3/20 of all candies and another 1.2 lb. the second student ate 3/5 of the candies and the remaining 0.3 lb. what weight of candies did they each eat?

The total weight of candies is unknown. Let x = the total weight of candies.

"One student ate 3/20 of all candies and another 1.2 lb":

The first student ate (3/20)x plus 1.2 lb which is 0.15x + 1.2.

"The second student ate 3/5 of the candies and the remaining 0.3 lb."

The second student ate (3/5)x and 0.3 lb which is 0.6x + 0.3.

Altogether the 2 students ate 0.15x + 1.2 + 0.6x + 0.3.

That was all the amount of candies, so that sum equals x.

0.15x + 1.2 + 0.6x + 0.3 = x

Now we solve the equation for x to find what the total amount of candies was.

0.75x + 1.5 = x

-0.25x = -1.5

x = 6

The total amount of candies was 6 lb.

The first student ate 0.15x + 1.2 = 0.15(6) + 1.2 = 0.9 + 1.2 = 2.1, or 2.1 lb of candies.

The second student ate 0.6x + 0.3 = 0.6(6) + 0.3 = 3.6 + 0.3 = 3.9, or 3.9 lb of candies.

The first student ate 2.1 lb of candies, and the second student ate 3.9 lb of candies.

answer4 to the second power is 16

and 4 to the third power is 64,

answer: 0.26

i used the calculator on google